x^2+0.29x+0.01=0

Solution for x^2+0.29x+0.01=0 equation:

x^2+0.29x+0.01=0

a = 1; b = 0.29; c = +0.01;
Δ = b2-4ac
Δ = 0.292-4·1·0.01
Δ = 0.0441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.29)-\sqrt{0.0441}}{2*1}=\frac{-0.29-\sqrt{0.0441}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.29)+\sqrt{0.0441}}{2*1}=\frac{-0.29+\sqrt{0.0441}}{2}
$